CSIR NET Result 2025: The Council of Scientific and Industrial Research has conducted the examination for Junior Research Fellowship & Assistant Professor from 28 February to 2nd March 2025. This examination aims to appoint candidates for assistant professor positions in various universities and colleges. It is expecting that the CSIR Result 2025 will be released in first week of April 2025. To access the result, candidates must log in to the website by entering their registration number and date of birth. Along with result, cut off marks will be available against their rank number. These cut off marks are the minimum threshold which candidates must meet to qualify for the examination. The qualified candidates will be able to download their scorecard, which will serve as the eligibility proof for further process. For more information read complete article.
CSIR NET 2025- Overview:-
Organisation | National Testing Agency (NTA) |
---|---|
Exam Name | JOINT CSIR-UGC NET (CSIR NET) |
Category | Sarkari Result |
Status | To be released |
CSIR NET Exam Date 2025 | 28th February, 1st March, and 2nd March 2025 |
CSIR NET Result 2025 | 1st week of April 2025 |
Selection Process | Computer-Based Test (CBT) |
Official Website | www.csirnet.nta.ac.in |
WhatsApp Group Link | JOIN NOW |

CSIR NET Cut Off 2025:-
The CSIR NET Cut Off will be release along with the result on the official website www.csirnet.nta.ac.in. Candidates can check the category-wise cut-off marks for each subject once published. Till then, here are the previous year’s cut-off marks:
Subjects | UR (%) | EWS (%) | OBC (%) | SC (%) | ST (%) | PwD (%) |
---|---|---|---|---|---|---|
Chemical Science | 59.00 | 51.50 | 51.00 | 39.25 | 30.50 | 25.00 |
Earth Science | 62.63 | 56.97 | 56.61 | 46.31 | 44.61 | 25.10 |
Life Science | 99.21 | 97.18 | 97.18 | 92.24 | 85.41 | 72.01 |
Mathematical Science | 54.88 | 47.63 | 47.13 | 36.00 | 29.63 | 26.13 |
Physical Science | 43.94 | 36.69 | 36.75 | 30.38 | 26.94 | 25.88 |
CSIR Result 2025 and Scorecard Link?
The CSIR UGC NET Result will be available on the official website www.csirnet.nta.ac.in. Once officially Out, we will also provide the direct result link here.
- The final merit list will be based on this objective-type test.
- NTA will publish two separate merit lists – one for Assistant Professorship and another for JRF (Junior Research Fellowship).
CSIR NET Minimum Qualifying Marks?
To qualify for JRF and Assistant Professor, candidates must secure the minimum qualifying marks as per their category. The require percentage is as follows:
Category | Minimum Qualifying Percentage |
---|---|
General, EWS, and OBC | 33% |
SC, ST, and PwD | 25% |
Steps to Check CSIR UGC NET 2025 Result?
- Open your internet browser and visit the official website: https://csirnet.nta.ac.in/.
- In the Latest News section, find and click on the link titled “DECLARATION OF SCORES OF THE JOINT CSIR NET December 2024 Exam”.
- You will be redirect to a new page.
- Enter your Application Number and Date of Birth in the required fields.
- Complete the captcha verification and click on the “Submit” button.
- Your CSIR UGC NET 2025 will be display on the screen.
- Check your subject-wise marks and download your CSIR NET Result and Scorecard for future reference.
Important Links:-
WhatsApp Group Link | JOIN NOW |
Official Website | CLICK HERE |
What After CSIR NET Result 2025?
After the declaration of the CSIR UGC NET Result, candidates should determine their next steps based on their eligibility:
- For JRF Qualified Candidates can apply for research fellowships in various institutions.
- For Assistant Professorship Qualified Candidates can pursue teaching opportunities in universities and colleges.
- For Other Career Opportunities candidates can explore Public Sector Units (PSUs) like ONGC, HPCL, and Indian Oil, which consider CSIR NET scores for recruitment.
FAQs:-
The CSIR NET Result 2025 is expected to be released in the 1st week of April 2025 on the official website www.csirnet.nta.ac.in.
Candidates can check their result by visiting the official website, clicking on the result link, and entering their Application Number and Date of Birth.